Question

find roots: 16x-10/x=27

Answer 1

16x²-10=27x
if x=2 ,then 16(2)²-10=27(2)
64-10=54
54=54
it means ,(x-2) is a factor of 16x²-27x-10=0
16x²-32x+5x-10=0
16x(x-2)+5(x-2)=0
(16x+5)(x-2)=0
16x+5=0,x-2=0

x=-16/5,x=2

Answer 2

$\bf \large \it{Hey \: User!!!}$

$<b> > > given 16x - 10/x = 27$
$<b> > > 16x - 10 = 27x$
$<b > > > 16x - 10 - 27x = 0$
$<b> > > - 11x - 10 = 0$
$<b > > > - 11x = 10$
$<b > > > x = - 10/11$

$<b > hence the root of the given equation is - 10/11$

$\bf \large \it{Cheers!!!}$