Question

Find roots of 6t-√t-2=0
Solution Text Explanation
Put √t=x
6x²-x-2=0
6x²-4x+3x-2=0
2x(3x-2)+1(3x-2)=0
(2x+1) (3x-2)=0
x=-1/2,2/3
" √t=-1/2 (not possible) "
√t=2/3
t=4/9
Here, why √t=-1/2 is not possible as it satisfies the equation​

Answer 1

Answer:

because I has only -1 and if we do this-1 we get x-1=0