Question

find roots of 6x2_2+2=0 by completing the square

Answer 1

6x²-2x+2=0
Divide In the Whole Equation By the Coffiecient of X².
x²-1/3x+2=0
Divide The Coffiecient of X by 2 and Add It's Square and Subtract It's Square.
x²-1/3x+(1/6)²-(1/6)²+2=0
(x-1/6)² = -2
(x-1/6) = ±√2
Now For Negative.
(x-1/6) = -√2
X = -√2+1/6
X = -√12+1/6
X = -2√3+1/6
X = -√3+1/3 Ans

Now For Positive.

(x-16) = √2
X = √2+1/6
X = √12+1/6
X = √3+1/3 Ans

Hope It Help You