Question

find roots of 9x^2-24x+16 by completing sqare method

Answer 1

Answer:

Step-by-step explanation:

9x² + 24x + 16 =0

divide whole equation by 9 ( coefficient of x2)

we get,

x² + 24x/9 + 16/9 = 0

transfer the c to right side

we get,

x² + 8/3x = - 16/9

Now third term ; [ 1/2 x coefficient of x ]²

= ( 1/2 x 8/3 )²

= ( 4/3)²

Now adding third term to both the sides,

we get,

x² + 8/3x + (4/3)² = -16/9 + (4/3)²

( x + 4/3 )² = -16/9 + 16/9

= ( x + 4/3)² = 0/9

= ( x + 4/3)² = 0

taking square root on both the sides,

we get,

root ( x + 4/3)² = root 0

= x + 4/3 = 0

x = - 4/3

Hope you like it

Answer 2

Answer:

Step-by-step explanation:

9x sq.-24x+16=0

9x sq.-(12+12)x+16=0

9x sq.-12x-12x+16

3x(3x-4)-4(3x-4)=0

(3x-4) (3x-4)=0

x=4/3,4/3