Question

find roots of equation x^2-4x+3=0

Answer 1

Step-by-step explanation:

x²-3x-x+3=0

x=3 x=1 OK friend

Answer 2

x² - 4x + 3 = 0

x² - 4x + 3 = 0express -4 as the sum of two numbers which give the product 3

x² - 4x + 3 = 0express -4 as the sum of two numbers which give the product 3=> x² - 3x -x + 3 = 0

x² - 4x + 3 = 0express -4 as the sum of two numbers which give the product 3=> x² - 3x -x + 3 = 0=> x(x - 3) -1(x -3) =0

x² - 4x + 3 = 0express -4 as the sum of two numbers which give the product 3=> x² - 3x -x + 3 = 0=> x(x - 3) -1(x -3) =0=> (x-1)(x-3) =0

x² - 4x + 3 = 0express -4 as the sum of two numbers which give the product 3=> x² - 3x -x + 3 = 0=> x(x - 3) -1(x -3) =0=> (x-1)(x-3) =0(x -1) =0 => x= 1

x² - 4x + 3 = 0express -4 as the sum of two numbers which give the product 3=> x² - 3x -x + 3 = 0=> x(x - 3) -1(x -3) =0=> (x-1)(x-3) =0(x -1) =0 => x= 1and (x-3)= 0 => x = 3

x² - 4x + 3 = 0express -4 as the sum of two numbers which give the product 3=> x² - 3x -x + 3 = 0=> x(x - 3) -1(x -3) =0=> (x-1)(x-3) =0(x -1) =0 => x= 1and (x-3)= 0 => x = 3So we get the roots 1 and 3

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