Question

find roots of quadratic equation

19x=7−6x
^2​

Answer 1

$19x = 7 - 6x {}^{2} \\ \\ = > - 6x {}^{2} - 19x + 7 = 0 \\ \\ = > - 6x {}^{2} - 21x + 2x + 7 = 0 \\ \\ = > - 3x(2x + 7) + 1(2x + 7) = 0 \\ \\ = > (2x + 7)( - 3x + 1) = 0 \\ \\ = > x = \frac{ - 7}{2} (or) \: x = \frac{1}{3}$

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Answer 2

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