Question

Find roots of quadratic equation 9x^2-3 (a+b)x+ab=0​

Answer 1

Answer:

the roots are a / 3 and b / 3

Step-by-step explanation:

$9 {x}^{2} - 3(a + b)x + ab = 0 \\ 9 {x}^{2} - 3ax - 3bx + ab = 0 \\ 3x(3x - a) - b(3x - a) = 0 \\ (3x - a)(3x - b) = 0 \\ 3x - a \: = 0 \: \: \: 3x - b = 0 \\ x = \frac{a}{3 \: } and \: x = \frac{b}{3}$