Question

*Find roots of quadratic equation by any method* .

1) m² + 5m + 5 = 0*

2) x² - 4x - 3 = 0*

3) (2a +3)² = 0*

4) n² -2n + 1= 0*

5) 3b² - 5b + 7 = 0*

6) 2y² - y + 2 = 0*

7) k² + 2k + 11= 0*
​​

Answer 1

Step-by-step explanation:

1)Use formula method

x= -b±√b²-4ac

2a

You will get roots as -5+√5 or -5-√5

2)Use split middle term method

x²-3x-x+3

(x-1)(x-3)

Roots are 1 or 3

3)(2a+3)(2a+3)=0

Only root is a= -3/2

4)n²-2n+1=0

(n-1)²=0

Only root is n=1

5)Use formula method

x= -b±√b²-4ac

2a

x=5±√25-84

6

x=5±√-59

6

x=5±√59i

6

Roots are imaginary

Here i is √-1