Question

Find roots of quadratic equation by factorisation:
x²-20x+1=0

Answer 1

Step-by-step explanation:

x²-20x+1=0

impossible by thia methods

Answer 2

GIVEN :-

• A quadratic equation x² - 20x + 1 = 0.

TO FIND :-

• The roots of the quadratic equation.

SOLUTION :-

As we know that,

$\\ : \implies \displaystyle \sf \: x = \frac{ - b \pm \sqrt{b ^{2} - 4ac } }{2a}$

• a = 1.
• b = -20.
• c = 1.

$\\ : \implies \displaystyle \sf \: x = \frac{ - ( - 20) \pm \sqrt{( - 20) ^{2} - 4 \times 1 \times 1} }{2 \times 1}$

$: \implies \displaystyle \sf \: x = \frac{20 \pm \sqrt{400 - 4} }{2}$

$: \implies \displaystyle \sf \: x = \frac{20 \pm \sqrt{396} }{2}$

$: \implies \displaystyle \sf \: x = \frac{20 - \sqrt{396} }{2} \: , \: x = \frac{20 + \sqrt{396} }{2}$

$: \implies \displaystyle \sf \: x = \frac{20 - 19.8 }{2} \: , \: x = \frac{20 + 19.8 }{2}$

$: \implies \displaystyle \sf \: x = \frac{20 - 20}{2} \: , \: x = \frac{20 + 20 }{2}$

$: \implies \displaystyle \sf \: x = \frac{0}{2} \: , \: x = \frac{40}{2}$

$: \implies \underline{ \boxed{\displaystyle \sf \: x = 0 \: , \: x = 20}}$