Question

find roots of quadratic equation by factorizing (2y+3)2-25=0​

Answer 1

Answer:

y= -4,1

Step-by-step explanation:

(2y +3)^2 -25=0

(2y+3)^2 =25

2y+3 =5

and

2y+3= -5

when

2y+3= 5,then

y=1

when 2y+3 =-5, then

y =-4