Question

find roots of quadratic equation by splitting the middle term x²+5x-6=0​

Answer 1

Answer:

$x {}^{2} + 5x - 6 = 0 \\ x {}^{2} + 6x - x - 6 = 0 \\ x(x + 6) - 1(x + 6) \\ (x + 6)(x - 1) \\ x = - 6 \\ x = 1$

Therefore, the roots of this quadratic equation are -6 and 1.

Step-by-step explanation:

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Answer 2

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Follow the steps :

1. x²+5x-6=0
2. x²+(-1+6)x-6=0
3. x²-x+6x-6=0
4. x(x-1)+6(x-1)=0
5. (x+6)(x-1)=0

Therefore value of x is -6 or 1.

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