Question

Find roots of quadratic equation x-1/x=3

Answer 1

$\mathbb{\huge{ANSWER - }}$


$\mathbb{METHOD \:OF\: \: SOLUTION:-}$

$x - \frac{1}{x} = 3 \\ \\ {x}^{2} - 1 = 3 \\ \\ \\ {x}^{2} = 3 + 1 \\ \\ {x}^{2} = 4 \\ \\ \\ x = + \sqrt{4} \\ \\ \\ \\ \\ x = - 2\\ \\ \\ x = + 2$


Hence,+2 and -2 are roots of this Quardratic Equation:-



Thanks!!

Answer 2

x-1/X=3

x²-1=3x
x²-3x-1=0
using dharacharya method

x=(3(+-)√9+4)/2
which is the required answer