Question

find roots of the eqn by middle term spliiting
1)
${x}^{2} - 3x - 4$
​

Answer 1

Answer:

×= -1 and 4

Step-by-step explanation:

${x}^{2} - 3x - 4 \\ {x}^{2} - 4x + x - 4 \\ x(x - 4) + 1(x - 4) \\ (x + 1)(x - 4) \\ (x + 1) = 0 \\ x = \: - 1 \\ (x - 4) = 0 \\ x = 4$

Answer 2

Answer:

${x}^{2} - 3x - 4 \\ {x}^{2} - 4x + x - 4 \\ x(x - 4) +1(x - 4) \\ ( x + 1) \: and \: (x - 4) \\ x = - 1 \: and \: x = 4$

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