Question

Find roots of the equatiom 3x^2-2x-5=0 by factorisation​

Answer 1

Answer:

x = 5/3, -1

Step-by-step explanation:

$3x^{2} - 2x - 5 = 0 \\3x^{2} + 3x - 5x - 5 = 0\\3x(x+1) - 5(x+1) = 0 \\(3x-5)(x+1) = 0 \\=> 3x - 5 = 0, 3x = 5, x = \frac{5}{3} \\=> x + 1 = 0, x = -1$