Question

find roots of the equation a^2-16a+48=0​

Answer 1

hope this will help you

Answer 2

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→find roots of the equation $a^2-16a+48=0​$

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⇒Given:

• $a^2-16a+48+0$

⇒To Find:

• Roots of equation

⇒Solution:

⇒$a^2-16a+48$

⇒$a^2-12a-4a+48$

⇒$a(a-12)-4(a-12)$

⇒$(a-12)(a-4)$

Roots are:-

⇒$\huge{\pink{\underbrace{\overbrace{12\: \& \: 4}}}}$

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