Question

find roots of the equation x^2-2x+3=0​

Answer 1

ANSWER....

BY QUADRATIC FORMULA.......

${x}^{2} - 2x + 3 = 0 \\ \\ a = 1 \\ b = - 2 \\ c = 3 \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x = \frac{ - ( - 2) + \sqrt{ {( - 2)}^{2} - 4(1)(3) } }{2(1)} \\ \\ x = \frac{2 + \sqrt{4 - 12} }{2} \\ \\ x = \frac{2 + \sqrt{ - 8} }{2} \\ \\ x = \frac{2 + 2 \sqrt{ - 2} }{2} \\ \\ x = 1 + i\sqrt{2} \: or \: 1 - i \sqrt{2}$

#BTSKINGDOM

^_^