Question

Find roots of the equation x^2+x-90=0 by only using quadratic formulae

Note:Roots which we get for this equation is rational.

Answer 1

$\Huge\mathcal{\underline{\blue{Answer\::-}}}$

Equation:-

$\purple{{x}^{2} + x - 90 = 0}$

So,

$a = 1, \: \: b = 1, \: \: c = - 90$

Then,

$d = {b}^{2} - 4ac$

$➟{1}^{2} - 4 \times 1 \times (- 90)$

$➠1 + 360$

$\pink{\bold{➡d = 360}}$

By the value of d we get x,

$➺x = \frac{ - b \pm \sqrt{d} }{2a}$

$➻x = \frac{ - 1 \pm\sqrt{361} }{1 \times 2}$

$➼x = \frac{ - 1 \pm \sqrt{361} }{2}$

$\orange{\boxed{\bold{➽x = \frac{ - 1 + \sqrt{361} }{2} \: \: or \: \: x = \frac{ - 1 - \sqrt{361} }{2}}}}$

Here's Is Ur Required Answer.

$\Huge\mathcal{\underline{\red{Hope\:It\: Helps\:U}}}$