Math, asked by mukul5576, 1 month ago

find roots of the equation ( Z- 3)³- 64 =0

Answers

Answered by chanchalprajaoati198

0

Step-by-step explanation:

x=−4,2±2√3i. Explanation: Notice that this is a sum of cubes, which is factorable as follows: a3+b3=(a+b)(a2−ab+b2). Thus, x3+64 is ...

Answered by kshitijgupta5680

0

Answer:

19

Step-by-step explanation:

(z-3)³ =64

(z-3) = cuberoot 64

z-3= 4

z= 3+4 =7

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