Question

find roots of the quadratic equation x-1/3=1/6 ?​

Answer 1

Step-by-step explanation:

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= > x - \frac{1}{3x} = \frac{1}{6} \\ \\ = > \frac{3x {}^{2} - 1 }{3x} = \frac{1}{6} \\ \\ = > 6(3x {}^{2} - 1) = 3x \\ \\ = > 18x {}^{2} - 6 = 3x \\ \\ = > 18x {}^{2} - 3x - 6 = 0 \\ \\ = > 3(6x {}^{2} - x - 2) = 0 \\ \\ = > 6 x{}^{2} - 4x + 3x - 2 = 0 \\ \\ = >2x(3x - 2) + 1(3x - 2) = 0 \\ \\ = > (2x + 1)(3x - 2) = 0 \\ \\ x = \frac{ - 1}{2} \: and \: x = \frac{2}{3 } \\ \\ so \: the \: roots \: are \: \frac{ - 1}{2} and \: \frac{2}{3}

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