Question

Find roots of x²+x+1=0

Answer 1

x2-x+1=0

Two solutions were found :

x =(1-√-3)/2=(1-i√ 3 )/2= 0.5000-0.8660i

x =(1+√-3)/2=(1+i√ 3 )/2= 0.5000+0.8660i

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring x2-x+1

The first term is, x2 its coefficient is 1 .

The middle term is, -x its coefficient is -1 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 1 • 1 = 1

Step-2 : Find two factors of 1 whose sum equals the coefficient of the middle term, which is -1 .

-1 + -1 = -2

1 + 1 = 2

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step 1 :

x2 - x + 1 = 0

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