Question

Find roots


$\sf \sqrt{2}x^{2} +7x+5\sqrt{2}$​

Answer 1

Answer:

Question :-

$\bf \: Find \: the \: roots \: of \: \sqrt{2} {x}^{2} + 7x + 5 \sqrt{2}$

To Find :-

• Find the roots

Solution :-

$\bf Here, \\ \bf \: We \: have \: to \: factor \: \sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 \\ \bf \: = \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2 } = 0 \\ \bf \: = x \sqrt{2} (x + \sqrt{2} ) + 5(x + \sqrt{2}) = 0 \\ \bf = (x \sqrt{2} + 5)(x + \sqrt{2} ) = 0 \\ \bf \: x = \frac{ - 5}{ \sqrt{2} } , - \sqrt{2}$

Hence ,

• $\bf \pink { \: Roots \: are \frac{ - 5}{ \sqrt{2} } ,- \sqrt{2} }$

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❥ @amritamohanty1472

Answer 2

$= \sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} \\ \\ = \sqrt{2} {x}^{2} + 5x + 2x + 5 \sqrt{2} \\ \\ x \sqrt{2} (x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0 \\ \\ (x \sqrt{2} + 5)(x + \sqrt{2} ) = 0 \\ \\ x = \frac{ - 5}{ \sqrt{2} } \: \: and \: \: - \sqrt{2}$