find S10 for an a.p. 1/2. 3/2. 5/2
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Answer:
a = 1/2
d= a2-a1= 3/2-1/2 = 2/2
d=1
n=10
Sn=n/2(2a+(n-1)d)
S10=10/2{2(1/2)+(10-1)1}
=5(1+9)
S10=5(10)
S10=50
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