find s10 for an ap 1/6 1/4 1/3
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Step-by-step explanation:
a = 1/6
d= 1/12
sum= n/2[2a+(n-1)d]
s10= 10/2[2×1/6+(9×1/12)]
= 5(1/3+3/4)
=5(13/12)
=65/12
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