Question

find S10 for an ap 1/6 , 1/6 , 1/3

Answer 1

Step-by-step explanation:

a = 1/6 , d = 1/2 , n = 10

S10 = ( 10/2 ) [ 2 × 1/6 + 9 × 1/2 ]

= 5 [ 1/3 + 9/2 ]

= ( 5/6 ) ( 2 + 27 )

= ( 5 × 29 ) / 6

= 145/6

I hope this helps you.

Answer 2

Answer:

I hope it will be helpful for you

Step-by-step explanation:

Sn = n/2 ( 2a+ n-1 × d )

a= 1/6 ,n = 10, d = 1/ 3

Sn = 10/2 ( 2× 1/6 + 10 - 1 × 1/3)

Sn = 10/2 (2/6 + 9 ×1/3)

Sn = 5 ( 1/3+9×1/3)

Sn = 5 ( 1/9 +9 )

Sn = 5(9/9)

Sn.= 5 (1)

Sn = 5