Question

Find s10, s31, s50 for an A. P 1,3,5,7

Answer 1

Answer:

S10 = 100

S31 = 1395

S50 = 3700

Step-by-step explanation:

Here,

first term (a) = 1

common difference (d) = 2

Now,

Sn = n/2 {2a + (n-1) d}

S10 = 10/2 { 2(1) + (10-1) 2 }

= 5 (20)

= 100

S10 = 100

Similarly,

S31 = 1395

and

S50 = 3700