find S12 if first term is 6 and last term is 9.
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Answer:
a
12
=37,d=3
a
12
=a+(12−1)d
37=a+(11×3)
37−33=a
a=4
s
12
=
2
12
[2a+(12−1)3]
s
12
=6[8+33]
s
12
=246
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