find s13 of an AP whose a7=6 and the common difference is 2
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Step-by-step explanation:
s13=n/2(2a+(n-1)d
s13=13/2(2×7 + 13-1 × 2
s13=13/2 (14 +24)
s13= 13/2 (38)
s13=494/2
s13=247
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