Find S15 if first term of ap is 10 ad common difference is 3
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a = 10
d = 3
S15 = 15/2 [2 x 10 + (14)3
= 15/2( 20 + 42 )
=465
bests seldon
d = 3
S15 = 15/2 [2 x 10 + (14)3
= 15/2( 20 + 42 )
=465
bests seldon
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