find S15 of an AP 1,7,13.....
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for these a.p.
a=t1=1
d=6
tn=a+(n-1)d
n=15
t15=1+14×6
t15=85
Sn=n/2 (t1+tn)
S15=15/2 ×(1+85)
S15=(15×86)/2
S15=1290/2
S15=645
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