Find S2 for the following given A.P. 3,5,7,9... .
Answers
Answered by
10
A1 = 3, A2 = 5
S2 = A1+A2 = 3+5 = 8
S2 = A1+A2 = 3+5 = 8
Answered by
5
It can be solved by the formula of ' sum of nth term "
It says
Sn=n/2[2a +(n-1)d], where 'n' is the 'no. of terms' and 'a' is the first term of the given A.P and 'd' is the common difference between first term and second term ( a2-a1 ).
Sol :- 'a1' = 3 and 'd' = a2-a1 = 5-3 = 2 and 'n' is 2 given
NOW, Sn = n/2 [2a + (n-1)d]
S2 = 2/2 [2(3) + (2-1)2]
=1 [6+2]
=8.
It says
Sn=n/2[2a +(n-1)d], where 'n' is the 'no. of terms' and 'a' is the first term of the given A.P and 'd' is the common difference between first term and second term ( a2-a1 ).
Sol :- 'a1' = 3 and 'd' = a2-a1 = 5-3 = 2 and 'n' is 2 given
NOW, Sn = n/2 [2a + (n-1)d]
S2 = 2/2 [2(3) + (2-1)2]
=1 [6+2]
=8.
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