find S30 of an Ap 10,15,20…30
Answers
Answered by
0
Answer:2475
Explanation:
Sn=n/2[2a+(n-1)d]
S30=30/2[2•10+(30-1)5]
=15[20+145]
=2475
Answered by
3
S(30) = 2,475
Explanation:
Given:
Ap 10,15,20…
First term(a) = 10
Common difference(d) = 15 - 10 = 5
Number of term(n) = 30
Find:
S(30)
Computation:
Sn = n/2[2a+(n-1)d]
S(30) = 30/2[2(10)+(30-1)5]
S(30) = 15[20+(29)5]
S(30) = 15[20+145]
S(30) = 15[165]
S(30) = 2,475
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https://brainly.in/question/20021644
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