Question

FIND S₈ IF THE S₅=175 AND A₁₀TERM=39
PLEASE SOLVE

Answer 1

A10=39
a+9d=39——(1)
S5=175
Sum of 5 terms of an AP is 5 times the middle term.
So 5A3=175
A3=35
a+2d=35——(2)
(1)-(2)——>
7d=4
d=4/7
From(2)
a=35-2d
=35-(2x4/7)
=35-8/7
=237/7

So this is an AP with first term 237/7 or 231 6/7 and common difference 4/7
So the AP is 237/7, 241/7, 245/7......

Answer 2

hope it will help uh ..

nd plz mark as brainliest ..☺☺