Question

find sa of the following
I) cuboid whose l= 25cm b=12cm h=10cm

ii)cube whose side is 12 cm

iii) cylinder whose r is 7cm and h=4cm​

Answer 1

Step-by-step explanation:

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Answer 2

Hello ridhimaa2575 !

Answer:

i) 1340 cm²

ii) 864 cm²

iii) 484 cm²

Step-by-step explanation:

Formulae :

Total Surface Area of a cuboid = 2[(l × b) + (b × h) + (h × l)], Where,

• l = Length of the Cuboid.
• b = Breadth of the Cuboid.
• h = Height of the Cuboid.

Total Surface Area of a Cube = 6s², Where,

• s is the Side of the Cube.

Total Surface Area of a Right Circular Cylinder = 2πr(r + h), Where,

• r is the Radius of the Base.
• h is the Height of the Cylinder.

Procedure :

i) Given :

l = 25 cm

b = 12 cm

h = 10 cm

Hence TSA of the cuboid = 2[(25 × 12) + (12 × 10) + (10 × 25)] cm²

⇒ TSA = 2[300 + 120 + 250] cm²

⇒ TSA = 2[670] cm²

∴ TSA = 1340 cm².

ii) Given :

s = 12 cm

Hence TSA of the Cube = 6(12)² cm²

⇒ TSA = 6(144) cm²

∴ TSA = 864 cm².

iii) Given :

r = 7 cm

h = 4 cm

Hence, TSA of the Right Circular Cylinder = 2π(7)(7 + 4) cm²

⇒ TSA = 2π(7)(11) cm²

Assuming π = 22/7,

⇒ TSA = (2 × 22 × 11) cm²

∴ TSA = 484 cm².

If π ≠ 22/7,

⇒ TSA = 2π(7)(11) cm²

∴ TSA = (154 × π) cm²

∴ TSA = 483.8 cm² [Approx. Value]

Thanks !