find sa of the following
I) cuboid whose l= 25cm b=12cm h=10cm
ii)cube whose side is 12 cm
iii) cylinder whose r is 7cm and h=4cm
Answers
Step-by-step explanation:
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Hello ridhimaa2575 !
Answer:
i) 1340 cm²
ii) 864 cm²
iii) 484 cm²
Step-by-step explanation:
Formulae :
Total Surface Area of a cuboid = 2[(l × b) + (b × h) + (h × l)], Where,
- l = Length of the Cuboid.
- b = Breadth of the Cuboid.
- h = Height of the Cuboid.
Total Surface Area of a Cube = 6s², Where,
- s is the Side of the Cube.
Total Surface Area of a Right Circular Cylinder = 2πr(r + h), Where,
- r is the Radius of the Base.
- h is the Height of the Cylinder.
Procedure :
i) Given :
l = 25 cm
b = 12 cm
h = 10 cm
Hence TSA of the cuboid = 2[(25 × 12) + (12 × 10) + (10 × 25)] cm²
⇒ TSA = 2[300 + 120 + 250] cm²
⇒ TSA = 2[670] cm²
∴ TSA = 1340 cm².
ii) Given :
s = 12 cm
Hence TSA of the Cube = 6(12)² cm²
⇒ TSA = 6(144) cm²
∴ TSA = 864 cm².
iii) Given :
r = 7 cm
h = 4 cm
Hence, TSA of the Right Circular Cylinder = 2π(7)(7 + 4) cm²
⇒ TSA = 2π(7)(11) cm²
Assuming π = 22/7,
⇒ TSA = (2 × 22 × 11) cm²
∴ TSA = 484 cm².
If π ≠ 22/7,
⇒ TSA = 2π(7)(11) cm²
∴ TSA = (154 × π) cm²
∴ TSA = 483.8 cm² [Approx. Value]
Thanks !