Find sec^2 A-tan^2 A if cos A =20/29, A is acute.whose 6
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Step-by-step explanation:
In this way:
(Without further information about the angle
A
, I assume that that angle is in the first quadrant)
sin
A
=
√
1
−
cos
2
A
=
√
1
−
25
169
=
√
169
−
25
169
=
=
√
144
169
=
12
13
,
and
tan
A
=
sin
A
cos
A
=
12
13
5
13
=
12
13
⋅
13
5
=
12
5
.
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