Question

find sec^2 theta - cot^2 (90-theta)/cosec^2 67° - tan^2 23° + (sin^2 40° + sin^2 50°)

Answer 1

without using trigonometric tables, prove that : sec2 (90 - theta) - cot2theta / 2( sin2 25 + sin2 65 ) + 2 cos2 60 tan2 28 tan2 62 / 3( sec2 43 - cot2 47 ) = 2/3 .

Answer 2

Halo there,

Refer the attachment for the answer.

Hope this helps...:)