Question

Find sec θ if θ is in Quadrant IV and sin θ = -1/5 PLZ HELP

Answer 1

Sinx = -1/5

sin²x = 1/25

Now,

cos²x = 1-sin²x

{by identity, sin²x+cos²x = 1}

cos²x = 1-1/25

cos²x = 25-1/25

cos²x = 24/25

cosx = √24/5

Now, we know,

secx = 1/cosx

so,

secx = 5/√24 or 5√6/12

Since the theta is in Quadrant IV the value will be positive, cause sec and cos remains positive in Quadrant IV

{ps:-I have taken x in place of theta}

Cheers!

Answer 2

Hope this help...........