find second and third term of an a.p. whose first term is –3 and common difference is –3.
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Answer:
Step-by-step explanation:
first term=-3
third term=-9
Answered by
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Step-by-step explanation:
let the first term of an ap be a1 = -3
let the common difference be d = -3
let 2nd term of an ap = a2
let 3rd term of an ap = a3
a2 = a1 + d
a2 = -3 + (-3)
a2 = -6
a3 = a1 + 2d
a3 = -3 + 2(-3)
a3 = -3 - 6
a3 = -9
so the second term of an ap is -6
so the second term of an ap is -6third term of an ap is -9
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