Question

find second and third term of an a.p. whose first term is –3 and common difference is –3.manishababar​

Answer 1

Step-by-step explanation:

T(n) = a+(n-1)×d

where a is first term -> -3

d is common difference -> -3

n is term number -> 1

Second term:

T(2) = -3+(2-1)×-3

= -3+1×-3

=-2×-3

= -6

Third term:

T(3) = -3+(3-1)×-3

= -3+2×-3

= -3-6

= -9

Answer 2

Given,

The first term of an A.P. is –3 and the common difference is –3.

To Find,

The second and third terms of the A.P. =?

Solution,

We can solve the question as follows:

It is given that the first term and common difference of an arithmetic progression are -3 and -3 respectively. We have to find the second and third terms.

$First\: term = -3$

$Common\: term = -3$

Now,

The nth term of an A.P. is given as:

$T_{n} = a +(n - 1)d$

Where,

$a = First\: term$

$n = nth\: term$

$d = Common\: difference$

Substituting the values to find the second and third terms,

$Second\: term = T_{2}$

$T_{2} = -3 + (2 - 1)(-3)$

    $= -3 + (-3)$

    $= -6$

$Third\: term = T_{3}$

$T_{3} = -3 + (3 - 1)(-3)$

    $= -3 + (-6)$

    $= -9$

   

Hence, the second and third terms are equal to -6 and -9 respectively.