Question

Find second and third term of an AP whose first term is -2
and common difference in -2.​

Answer 1

Answer:

a2= -2-2=-4

a3= -2+2*-2=-6

Answer 2

Step-by-step explanation:

$a = - 2 \: d = - 2 \\ tn = a + (n - 1)d \\ t2 = - 2 + (2 - 1)( - 2) \\ \: \: \: \: \: = - 2 + (1)( - 2) \\ \: \: \: \: \: = - 2 - 2 \\ t2= - 4 \\ t3 = - 2(3 - 1)( - 2) \\ \: \: \: \: \: = - 2 + (2)( - 2) \\ \: \: \: \: \: = - 2 - 4 \\ t3 = -6$

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