Math, asked by samdhaliwal, 1 year ago

find seventh root of 0.03457
in logarithms​

Answers

Answered by chbilalakbar
3

Answer:

x = 0.6184

Step-by-step explanation:

let x be 7th root of 0.03457 then

x^7 = 0.03457

taking log on both sides we get

㏒( x^7 ) = ㏒( 0.03457 )

we know that

㏒( 0.03457 ) = -1.4613

So

㏒( x^7 ) = -1.4613

and we know that

㏒( x^7 ) = 7 × ㏒ x

so

7 × ㏒( x ) = -1.4613

Dividing by 7 and taking anti log on both sides we get

x = 0.6184

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