find seventh root of 0.03457
in logarithms
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Answer:
x = 0.6184
Step-by-step explanation:
let x be 7th root of 0.03457 then
x^7 = 0.03457
taking log on both sides we get
㏒( x^7 ) = ㏒( 0.03457 )
we know that
㏒( 0.03457 ) = -1.4613
So
㏒( x^7 ) = -1.4613
and we know that
㏒( x^7 ) = 7 × ㏒ x
so
7 × ㏒( x ) = -1.4613
Dividing by 7 and taking anti log on both sides we get
x = 0.6184
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