Find shaded region if AB = 6cm , AC = 8 cm .
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Answer:
40 CM
Step-by-step explanation:
AB = 6 CM
AC = 8 CM
BC = 6^2+8^2
= 36+64
=100
= 10^2 = 10 CM
SO WE CAN SAY ,
BC IS A DIAMETER OF THE SEMICIRCLE ACB
RADIUS = 10/2 = 5
THEN AREA OF SEMICIRCLE = PIE R^2/2
= (22/7*5*5)/2
= 11/7*25
= 275/7 CM
BA IS A DIAMETER OF SEMICIRCLE BEA
THEN RADIUS =6/2 = 3
AREA = (22/7*3*3)/2
= 11/7*9
= 99/7
AC IS A DIAMETER OF SEMICIRCLE AFC
THEN RADIUS = 8/2 = 4 CM
AREA = (22/7*4*4)/2
= 11/7*16
= 176/7
=AREA OF TRIANGLE = 1/2 BASE HEIGHT
= 1/2*10*8
=5*8=40 CM^2
AREA OF TRIANGLE-AREA OF CIRCLE = 275/7-40*7/7
=280-275/7
=5/7CM
AREA OF SHADED REGION = 176/7+99/7+5/7
=280/7
= 40 CM
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