Question

find side of a rhombus where its diagonals are 16,9 cm​

Answer 1

Hey mate

Here is your answer

As we know that the diagonals of a rhombus bisect each other at 90°............

${side}^{2} = { \frac{1}{2}diagonal }^{2} + \frac{1}{2} {diagonal}^{2} \\ {s}^{2} = {8}^{2} + {4.5}^{2} \\ {s}^{2} = 64 + 20.25 \\ {s}^{2} = 84.25 \\ s = </u><u>9</u><u>.</u><u>1</u><u>7</u><u>$

hope it helps u ......

Answer 2

s=9.17okkk please follow me,,❤️❤️❤️