find side of a rhombus whose diagonal is 16cm and 12cm
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ᴀʟʟ sɪᴅᴇs ᴏғ ᴀ ʀʜᴏᴍʙᴜs ᴀʀᴇ ᴇǫᴜᴀʟ ɪɴ ʟᴇɴɢᴛʜ.
ᴛʜᴇ ᴅɪᴀɢᴏɴᴀʟs ᴏғ ᴛʜᴇ ʀʜᴏᴍʙᴜs ɪɴᴛᴇʀsᴇᴄᴛ ᴀᴛ ᴀ 90 ᴅᴇɢʀᴇᴇ ᴀɴɢʟᴇ.
ᴛʜᴇ ᴅɪᴀɢᴏɴᴀʟs ᴀɴᴅ ᴛʜᴇ sɪᴅᴇs ᴏғ ᴛʜᴇ ʀʜᴏᴍʙᴜs ғᴏʀᴍ ʀɪɢʜᴛ ᴛʀɪᴀɴɢʟᴇs.
ᴏɴᴇ ʟᴇɢ ᴏғ ᴛʜᴇsᴇ ʀɪɢʜᴛ ᴛʀɪᴀɴɢʟᴇs ɪs ᴇǫᴜᴀʟ ᴛᴏ 8 ᴄᴍ ɪɴ ʟᴇɴɢᴛʜ.
ᴛʜᴇ ᴏᴛʜᴇʀ ʟᴇɢ ᴏғ ᴛʜᴇsᴇ ʀɪɢʜᴛ ᴛʀɪᴀɴɢʟᴇs ɪs ᴇǫᴜᴀʟ ᴛᴏ 6 ᴄᴍ ɪɴ ʟᴇɴɢᴛʜ
ᴛʜᴀᴛ ᴡᴏᴜʟᴅ ʙᴇ ʜᴀʟғ ᴛʜᴇ ʟᴇɴɢᴛʜ ᴏғ ᴇᴀᴄʜ ᴅɪᴀɢᴏɴᴀʟ.
ᴛʜᴇ sɪᴅᴇs ᴏғ ᴛʜᴇ ᴛʀɪᴀɴɢʟᴇ ғᴏʀᴍ ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ ᴏғ ᴛʜᴇsᴇ ʀɪɢʜᴛ ᴛʀɪᴀɴɢʟᴇs.
ᴛʜᴇ ғᴏʀᴍᴜʟᴀ ɪs:
ʜʏᴘᴏᴛᴇɴᴜsᴇ sǫᴜᴀʀᴇᴅ = ᴏɴᴇ ʟᴇɢ sǫᴜᴀʀᴇᴅ ᴘʟᴜs ᴏᴛʜᴇʀ ʟᴇɢ sǫᴜᴀʀᴇᴅ.
ᴛʜɪs ᴍᴀᴋᴇs ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ sǫᴜᴀʀᴇᴅ ᴇǫᴜᴀʟ ᴛᴏ 8² + 6² = 64 + 36 = 100
ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ ɪs ᴛʜᴇ sǫᴜᴀʀᴇ ʀᴏᴏᴛ ᴏғ 100 ᴡʜɪᴄʜ ᴍᴀᴋᴇs ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ ᴇǫᴜᴀʟ ᴛᴏ 10.
ᴀʟʟ sɪᴅᴇs ᴏғ ᴀ ʀʜᴏᴍʙᴜs ᴀʀᴇ ᴇǫᴜᴀʟ ɪɴ ʟᴇɴɢᴛʜ.
ᴛʜᴇ ᴅɪᴀɢᴏɴᴀʟs ᴏғ ᴛʜᴇ ʀʜᴏᴍʙᴜs ɪɴᴛᴇʀsᴇᴄᴛ ᴀᴛ ᴀ 90 ᴅᴇɢʀᴇᴇ ᴀɴɢʟᴇ.
ᴛʜᴇ ᴅɪᴀɢᴏɴᴀʟs ᴀɴᴅ ᴛʜᴇ sɪᴅᴇs ᴏғ ᴛʜᴇ ʀʜᴏᴍʙᴜs ғᴏʀᴍ ʀɪɢʜᴛ ᴛʀɪᴀɴɢʟᴇs.
ᴏɴᴇ ʟᴇɢ ᴏғ ᴛʜᴇsᴇ ʀɪɢʜᴛ ᴛʀɪᴀɴɢʟᴇs ɪs ᴇǫᴜᴀʟ ᴛᴏ 8 ᴄᴍ ɪɴ ʟᴇɴɢᴛʜ.
ᴛʜᴇ ᴏᴛʜᴇʀ ʟᴇɢ ᴏғ ᴛʜᴇsᴇ ʀɪɢʜᴛ ᴛʀɪᴀɴɢʟᴇs ɪs ᴇǫᴜᴀʟ ᴛᴏ 6 ᴄᴍ ɪɴ ʟᴇɴɢᴛʜ
ᴛʜᴀᴛ ᴡᴏᴜʟᴅ ʙᴇ ʜᴀʟғ ᴛʜᴇ ʟᴇɴɢᴛʜ ᴏғ ᴇᴀᴄʜ ᴅɪᴀɢᴏɴᴀʟ.
ᴛʜᴇ sɪᴅᴇs ᴏғ ᴛʜᴇ ᴛʀɪᴀɴɢʟᴇ ғᴏʀᴍ ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ ᴏғ ᴛʜᴇsᴇ ʀɪɢʜᴛ ᴛʀɪᴀɴɢʟᴇs.
ᴛʜᴇ ғᴏʀᴍᴜʟᴀ ɪs:
ʜʏᴘᴏᴛᴇɴᴜsᴇ sǫᴜᴀʀᴇᴅ = ᴏɴᴇ ʟᴇɢ sǫᴜᴀʀᴇᴅ ᴘʟᴜs ᴏᴛʜᴇʀ ʟᴇɢ sǫᴜᴀʀᴇᴅ.
ᴛʜɪs ᴍᴀᴋᴇs ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ sǫᴜᴀʀᴇᴅ ᴇǫᴜᴀʟ ᴛᴏ 8² + 6² = 64 + 36 = 100
ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ ɪs ᴛʜᴇ sǫᴜᴀʀᴇ ʀᴏᴏᴛ ᴏғ 100 ᴡʜɪᴄʜ ᴍᴀᴋᴇs ᴛʜᴇ ʜʏᴘᴏᴛᴇɴᴜsᴇ ᴇǫᴜᴀʟ ᴛᴏ 10.
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Question:-
The lengths of the diagonals of a rhombus are 16cm and 12cm. then find the length of the side of rhombus
Solution:-
we know that diagonal of rhombus,bisect each other in right angle ( 90° ).
we also know that all sides of rhombus are equal ( of equal length ).
so, now
Let rhombus is ABCD
Let, diagonal of rhombus
BD = 16 cm and AC = 12 cm
means,
OD = 8 cm and AO = 6 cm
By pythagorus theorem
To find length of AD ( and all side of rhombus )
=> (AD)² = (OD)² + (AO)²
=> (AD)² = (8)² + (6)²
=> (AD)² = 64 + 36
=> (AD)² = 100
=> AD = √100
=> AD = 10 cm
Hence length of all side of rhombus
is 10 cm.
i hope it helps you.
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