find side of the cube whose surface area is 432m^2.
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2
Solution :
Let the side of the cube = a m
Surface area of the cube = 432 m²
=> 6a² = 432 m²
=> a² = 432/6
=> a² = 72
=> a = √72
=> a = √( 6 × 6 × 2 )
=> a = 6√2 m
••••
Let the side of the cube = a m
Surface area of the cube = 432 m²
=> 6a² = 432 m²
=> a² = 432/6
=> a² = 72
=> a = √72
=> a = √( 6 × 6 × 2 )
=> a = 6√2 m
••••
Answered by
1
Surface area of cube =6l^2=432
l^2=432/6=72
l=√72=8.49
l^2=432/6=72
l=√72=8.49
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