Question

find sides of a triangle with area 910 metre square​

Answer 1

Answer:

22

The base and height are equal because the triangle is right angle isosceles triangle

Consider them as b=h=X

Now applying area of triangle formula and solving we get

X^2=242

X=√121×2

X=11√2

Now by applying pythagoras theorem

Base^2+height^2=hypotenuse^2

X^2+X^2=h^2

(11√2)^2+(11√2)^2=h^2

242+242=h^2

484=h^2

H=22

Answer 2

Step-by-step explanation:

Answer:

22

The base and height are equal because the triangle is right angle isosceles triangle

Consider them as b=h=X

Now applying area of triangle formula and solving we get

X^2=242

X=√121×2

X=11√2

Now by applying pythagoras theorem

Base^2+height^2=hypotenuse^2

X^2+X^2=h^2

(11√2)^2+(11√2)^2=h^2

242+242=h^2

484=h^2

H=22