Question

find simple interest 9 monthly in 47000 principal 12​

Answer 1

Answer:

Hi mate...!!!

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Here is your answer

From, p*r*t/100

12*9*47000/100

50760...... Answer

Hope you understand

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Answer 2

FULL QUESTION:

find simple interest 9 monthly in 47000 principal 12% rate.

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=4230\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 9\: month} \\ \\ : \implies \text{Principal(p) = 47000\:rupees} \\ \\ : \implies \text{Rate(r) = 12\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{47000 \times 12 \times\frac{9} {12} }{100} \\ \\ : \implies S.I = \frac{470\times108 }{12} \\ \\ \green{ : \implies \text{S.I= 4230\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =4230\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$