Question

Find Simple Interest and amount on Rs. 12000 for 1 year at the rate of 10% per annum.​

Answer 1

Answer:

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}\end{gathered}$

• ➳ Principle = Rs.12000
• ➳ Rate of Interest = 10%
• ➳ Time = 1 year

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{To Find :}}}}}}\end{gathered}$

• ➳ Simple Interest

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{Using Formula :}}}}}}\end{gathered}$

$\quad\dag{\underline{\boxed{\sf{\purple{ S.I = \dfrac{P \times R \times T}{100}}}}}}$

Where

• S.I = Simple Interest
• P = Principle
• R = Rate of Interest
• T = Time Period

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{Basic Terms :}}}}}}\end{gathered}$

• ➽ Simple Interest = Simple interest is the method of calculating interest charged on the amount invested in a fixed deposit.
• ➽ Principle = The principal is the amount due on any debt before interest, or the amount invested before returns
• ➽ Rate = An interest rate is the percentage of principal charged by the lender for the use of its money
• ➽ Time = Time is duration (in months or years) in Simple Interest

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}\end{gathered}$

★ Here

$\quad{: \implies{\tt{Principle = Rs.12000}}}$

$\quad{: \implies{\tt{Rate \: of \: Interest = 10 \%}}}$

$\quad{: \implies{\tt{Time = 1 \: year}}}$

$\rule{200}2$

★ Calculating the Simple Interest

$\quad{: \longmapsto{\tt{ S.I = \dfrac{P \times R \times T}{100}}}}$

• Substituting the values

$\quad{: \longmapsto{\tt{ S.I = \dfrac{12000 \times 10 \times 1}{100}}}}$

$\quad{: \longmapsto{\tt{ S.I = \dfrac{120000}{100}}}}$

$\quad{: \longmapsto{\tt{ S.I = \cancel{\dfrac{120000}{100}}}}}$

$\quad{: \longmapsto{\tt{ S.I ={Rs.1200}}}}$

$\quad\bigstar{\underline{\boxed{\tt{\purple{ S.I ={Rs.1200}}}}}}$

${\therefore{\underline{\underline{\pmb{\frak{The \: Simple \: Interest \: is \: {\sf{\red{Rs.1200.}}}}}}}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{Learn More :}}}}}}\end{gathered}$

$\quad\circ{\underline{\boxed{\sf{\purple{A ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}$

$\quad\circ{\underline{\boxed{\sf{\red{Amount = Principle + Interest}}}}}$

$\quad\circ{\underline{\boxed{\sf{\purple{ P=Amount - Interest }}}}}$

$\quad\circ{\underline{\boxed{\sf{\red{ S.I = \dfrac{P \times R \times T}{100}}}}}}$

$\quad\circ{\underline{\boxed{\sf{\purple{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}}}}}}$

$\quad\circ{\underline{\boxed{\sf{\red{P = \dfrac{Interest \times 100 }{Time \times Rate}}}}}}$

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Answer 2

Question:

Find Simple Interest and amount on Rs. 12000 for 1 year at the rate of 10% per annum.

Answer:

Rs. 1200

explanation-step-by-step:

$\pink{◆ We\:have\: to \:find\: simple\: interest\: ! \:}$

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{◆ Formula required:}}}}}}\end{gathered}$

$\: \: \: \: \:\diamond{\underline{\boxed{\sf{\pink{ Interset = \dfrac{P \times R \times T}{100}}}}}}$

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}\end{gathered}$

Principal = Rs 12,000.

Time = 1 year

Rate = 10%

$\: \: \: \: \:\diamond{\underline{\boxed{\sf{\red{ Interset = \dfrac{P \times R \times T}{100}}}}}}$

$\: \: \: \: \:\diamond{\underline{\boxed{\sf{\purple{ Interset = \dfrac{12000 \times 10\times 1}{100}}}}}}$

$\: \: \: \: \:\diamond{\underline{\boxed{\sf{\red{ Interset = \dfrac {12000 \times 10}{100}}}}}}$

$\: \: \: \: \:\diamond{\underline{\boxed{\sf{\purple{ Interset = \cancel\dfrac {120000}{100}}}}}}$

$\: \: \: \: \:\diamond{\underline{\boxed{\sf{\red{ Interset ={ 1200}}}}}}$

$\purple{ \star{\tt{ hence \: the \: simple \: interest \:= Rs. 1200{}{}}}}$

_______________________________

$\begin{gathered}{\large{\textsf{\textbf{\underline{\underline{Learn More :}}}}}}\end{gathered}$

$\: \: \: \: \:\star{\underline{\boxed{\sf{\purple{ S.I = \dfrac{P\times R × T}{100}}}}}}$

$\: \: \: \: \:\diamond{\underline{\boxed{\sf{\red{ P = \dfrac{100 \times S. I}{R \times T }}}}}}$

$\: \: \: \: \:\star{\underline{\boxed{\sf{\blue{ R = \dfrac{100 \times S. I}{P \times T}}}}}}$

$\: \: \: \: \:\diamond{\underline{\boxed{\sf{\pink{ T = \dfrac{100 \times si}{p \times r}}}}}}$

________________________