Question

find simple interest and amount - principal=250000 rate=2.5percent time= 2year 4 months

Answer 1

Simple interest_ P×R×T/100
time_2×4/12
note putting values in this formula.
250000×2.5×8/100
₹50000 simple interest
and amount is SI+Principal
50000+250000
amount is ₹300000

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=14583.33\:rupees}}}$

$\green{\therefore{\text{Amount=264583.33\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 2\:years\:4\:months} \\ \\ : \implies \text{Principal(p) =2,50,000\:rupees} \\ \\ : \implies \text{Rate(r) = 2.5\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}\\\\ :\implies \text{Amount(A)=?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{250000\times 2.5 \times\frac{28}{12} }{100} \\ \\ : \implies S.I = \frac{250000\times 2.5\times 28}{ 100\times 12} \\ \\ \green{ : \implies \text{S.I= 14583.33\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest = 14583.33\: rupees}} \\ \\ :\implies \text{Amount=S.I+Principal}\\\\ \green{:\implies \text{Amount=14583.33+250000=264583.33\:ruppes}}\\\\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$