Question

find simple interest and the amount when principal=Rs 9600,rate=3.5%p.a. and time=3months

Answer 1

hey mate

here is your Answer


find simple interest and the amount when principal=Rs 9600,rate=3.5%p.a. and time=3months??

solution:-

formulae= simple interest =P×R×T/100


principle=₹9600


Rate=3.5%


time=3 months


solve:-

=> 9600×3.5×3/100

=> 96×3.5×3

=> 336×3

=> 1,008


simple interest is 1,008

then,amount =Simple interest+principal

amount=1,008+9600

amount =10,608


I hope this answer helps you


thank you
be brainly

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=84\:rupees}}}$

$\green{\therefore{\text{Amount=9684\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 3\:months} \\ \\ : \implies \text{Principal(p) = 9600\:rupees} \\ \\ : \implies \text{Rate(r) = 3.5\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}\\\\ :\implies \text{Amount=?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{9600 \times 3.5\times0.25}{100} \\ \\ : \implies S.I = \frac{9600 \times0.875 }{100 } \\ \\ \green{ : \implies \text{S.I= 84\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =84\: rupees}} \\ \\ :\implies Amount=S.I+principal\\\\ \green{:\implies\text{Amount=84+9600=9684\:rupees}} \\\\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$