Question

Find simple interest if P=20,000, R=41% per annum and T= 2 years.​

Answer 1

SI = PNR

= 20,000 x 2 x 0.41

= 16,400

Answer 2

Given : Principal (P) is 20,000 , Rate of Interest (R) is 41% p.a & Time is 2 yrs .

Exigency to find : Simple Interest.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀Finding Simple interest :

$\dag\:\:\it{ As,\:We\:know\:that\::}$

$\qquad \dag\:\:\bigg\lgroup \sf{ Simple \:Interest \:: \dfrac { P \times R \times T }{100} }\bigg\rgroup$

⠀⠀⠀⠀⠀Here P is the Principal , R is the Rate of Interest & T is the Time Taken .

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{20,000 \times 41 \times 2 }{100}$

$\qquad \longmapsto \sf Simple \:Interest \:= \dfrac{20,0\cancel {00}\times 41 \times 2 }{\cancel {100}}$

$\qquad \longmapsto \sf Simple \:Interest \:= 200 \times 41 \times 2$

$\qquad \longmapsto \sf Simple \:Interest \:= 8,200 \times 2$

$\qquad \longmapsto \frak{\underline{\purple{\:Simple \:Interest\:= Rs.16,400\: }} }\:\:\:\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Simple \:\:Interest \:is\:\bf{Rs.16,400.}}}}$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀